[chimerax-users] Distance between two atoms
McClean, Phillip
phillip.mcclean at ndsu.edu
Tue Nov 15 15:25:45 PST 2022
Hi Elaine,
Hi Elaine,
Well I am having fish tonight 😉. I used your suggestion select the atoms on the screen and then run the pop-up distance command and reading the results in the Log. I am still not fully clear about defining atoms and such after reading the atoms page. I will keep working on it.
Thanks for your help.
Phil
________________________________
From: Elaine Meng <meng at cgl.ucsf.edu>
Sent: Tuesday, November 15, 2022 11:03 AM
To: McClean, Phillip <phillip.mcclean at ndsu.edu>
Cc: chimerax-users at cgl.ucsf.edu <chimerax-users at cgl.ucsf.edu>
Subject: Re: [chimerax-users] Distance between two atoms
Hi Phil,
There is a "distance" command, use command "help distance" or see the help at our website here:
<https://rbvi.ucsf.edu/chimerax/docs/user/commands/distance.html>
...and many examples of how to specify atoms in the command line here:
<https://rbvi.ucsf.edu/chimerax/docs/user/commands/atomspec.html#hierarchy>
Why don't you give it a few tries? We need to "teach a man to fish" since we can't tell thousands of users how to write each command they need for their research.
Or you can just choose the atoms from the screen: first make sure they are displayed so you can actually see them, and then Ctrl-click one, Shift-Ctrl-doubleclick the second one and choose "Distance" from the resulting pop-up menu. This also is described in the help (Selection Context Menus):
<https://rbvi.ucsf.edu/chimerax/docs/user/selection.html#context>
Best,
Elaine
-----
Elaine C. Meng, Ph.D.
UCSF Chimera(X) team
Department of Pharmaceutical Chemistry
University of California, San Francisco
> On Nov 15, 2022, at 8:30 AM, McClean, Phillip via ChimeraX-users <chimerax-users at cgl.ucsf.edu> wrote:
>
> Hi Everyone,
>
> I have a two chain model. I would like to determine the distance between the CD1 atom of residue 77 in chain B and the CD1 atom of residue Leu 150 in chain C. What would be the proper distance command.
>
> Thanks for the help again.
>
> Phil McClean
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